ZHCSJQ2A May   2019  – August 2019 TPS2596

PRODUCTION DATA.  

  1. 1 特性
  2. 2 应用
  3. 3 说明
    1.     Device Images
      1.      简化原理图
      2.      TPS25963x 1KV EFT 响应
  4. 4 修订历史记录
  5. 5 器件比较表
  6. 6 Pin Configuration and Functions
    1.     Pin Functions
  7. 7 Specifications
    1. 7.1 Absolute Maximum Ratings
    2. 7.2 ESD Ratings
    3. 7.3 Recommended Operating Conditions
    4. 7.4 Thermal Information
    5. 7.5 Electrical Characteristics
    6. 7.6 Timing Requirements
    7. 7.7 Switching Characteristics
    8. 7.8 Typical Characteristics
  8. 8 Detailed Description
    1. 8.1 Overview
    2. 8.2 Functional Block Diagram
    3. 8.3 Feature Description
      1. 8.3.1 Undervoltage Protection (UVP) and Undervoltage Lockout (UVLO)
      2. 8.3.2 Overvoltage Protection
        1. 8.3.2.1 Overvoltage Lockout
        2. 8.3.2.2 Overvoltage Clamp
      3. 8.3.3 Inrush Current, Overcurrent and Short Circuit Protection
        1. 8.3.3.1 Slew Rate and Inrush Current Control (dVdt)
        2. 8.3.3.2 Active Current Limiting
        3. 8.3.3.3 Short-Circuit Protection
      4. 8.3.4 Analog Load Current Monitor (IMON)
      5. 8.3.5 Overtemperature Protection (OTP)
      6. 8.3.6 Fault Indication
    4. 8.4 Device Functional Modes
      1. 8.4.1 Enable and Fault Pin Functional Mode 1: Single Device, Self-Controlled
      2. 8.4.2 Enable and Fault Pin Functional Mode 2: Single Device, Host-Controlled
      3. 8.4.3 Enable and Fault Pin Functional Mode 3: Multiple Devices, Self-Controlled
  9. 9 Application and Implementation
    1. 9.1 Application Information
    2. 9.2 Typical Application
      1. 9.2.1 Precision Current Limiting and Protection for White Goods
      2. 9.2.2 Design Requirements
      3. 9.2.3 Detailed Design Procedure
        1. 9.2.3.1 Programming the Current-Limit Threshold: RILM Selection
        2. 9.2.3.2 Undervoltage and Overvoltage Lockout Set Point
        3. 9.2.3.3 Setting Output Voltage Ramp Time (TdVdT)
          1. 9.2.3.3.1 Case 1: Start-Up Without Load. Only Output Capacitance COUT Draws Current
          2. 9.2.3.3.2 Case 2: Start-Up With Load. Output Capacitance COUT and Load Draw Current
      4. 9.2.4 Support Component Selection: RFLT and CIN
      5. 9.2.5 Application Curves
    3. 9.3 System Examples
      1. 9.3.1 Current Limiting and Overvoltage Protection and for Energy Meter Power Rails
      2. 9.3.2 Precision Current Limiting and Protection in Appliances
  10. 10Power Supply Recommendations
    1. 10.1 Transient Protection
    2. 10.2 Output Short-Circuit Measurements
  11. 11Layout
    1. 11.1 Layout Guidelines
    2. 11.2 Layout Example
  12. 12器件和文档支持
    1. 12.1 文档支持
      1. 12.1.1 相关文档
    2. 12.2 接收文档更新通知
    3. 12.3 社区资源
    4. 12.4 商标
    5. 12.5 静电放电警告
    6. 12.6 Glossary
  13. 13机械、封装和可订购信息

封装选项

机械数据 (封装 | 引脚)
散热焊盘机械数据 (封装 | 引脚)
订购信息

9.2.3.2 Undervoltage and Overvoltage Lockout Set Point

The undervoltage lockout (UVLO) and overvoltage lockout (OVLO) trip point is adjusted using the external voltage divider network of R1, R2 and R3as connected between IN, EN/UVLO, OVLO and GND pins of the device. The values required for setting the undervoltage and overvoltage are calculated solving Equation 8 and Equation 9.

Equation 8. TPS2596 Apps-section-equation-3.gif
Equation 9. TPS2596 Apps-section-equation-2.gif

Where VUVLO(R) is UVLO rising threshold (1.2 V). Because R1, R2 and R3 leak the current from input supply VIN, these resistors must be selected based on the acceptable leakage current from input power supply VIN.

The current drawn by R1, R2 and R3 from the power supply is IR123 = VIN / (R1 + R2 + R3).

However, leakage currents due to external active components connected to the resistor string can add error to these calculations. So, the resistor string current, IR123 must be chosen to be 20 times greater than the leakage current expected.

From the device electrical specifications, VOVLO = 1.2 V and VUVLO = 1.2 V. For design requirements, VOV = 13.7 V and VUV = 8 V. To solve the equation, first choose the value of R3 = 47 kΩ and use Equation 9 to solve for (R1 + R2) = 489.58 kΩ. Use Equation 8 and value of (R1 + R2) to solve for R2 = 33.48 kΩ and finally R1= 456.1 kΩ. Using the closest standard 1% resistor values gives R1 = 464 kΩ, R2 = 33.2 kΩ, and R3 = 47.5 kΩ.