SLOS075J November 1979 – January 2015 NE5532 , NE5532A , SA5532 , SA5532A

PRODUCTION DATA.

- 1 Features
- 2 Applications
- 3 Description
- 4 Simplified Schematic
- 5 Revision History
- 6 Pin Configuration and Functions
- 7 Specifications
- 8 Detailed Description
- 9 Application and Implementation
- 10Power Supply Recommendations
- 11Layout
- 12Device and Documentation Support
- 13Mechanical, Packaging, and Orderable Information

NOTE

Information in the following applications sections is not part of the TI component specification, and TI does not warrant its accuracy or completeness. TI’s customers are responsible for determining suitability of components for their purposes. Customers should validate and test their design implementation to confirm system functionality.

Some applications require differential signals. Figure 4 shows a simple circuit to convert a single-ended input of 2 V to 10 V into differential output of ±8 V on a single 15-V supply. The output range is intentionally limited to maximize linearity. The circuit is composed of two amplifiers. One amplifier acts as a buffer and creates a voltage, V_{OUT+}. The second amplifier inverts the input and adds a reference voltage to generate V_{OUT–}. Both V_{OUT+} and V_{OUT–} range from 2 V to 10 V. The difference, V_{DIFF}, is the difference between V_{OUT+} and V_{OUT–}.

The design requirements are as follows:

- Supply voltage: 15 V
- Reference voltage: 12V
- Input: 2 V to 10 V
- Output differential: ±8 V

The circuit in Figure 4 takes a single-ended input signal, V_{IN}, and generates two output signals, V_{OUT+} and V_{OUT–} using two amplifiers and a reference voltage, V_{REF}. V_{OUT+} is the output of the first amplifier and is a buffered version of the input signal, V_{IN}Equation 1. V_{OUT–} is the output of the second amplifier which uses V_{REF} to add an offset voltage to V_{IN} and feedback to add inverting gain. The transfer function for V_{OUT–} is Equation 2.

Equation 1. V_{OUT+} = V_{IN}

Equation 2.

The differential output signal, V_{DIFF}, is the difference between the two single-ended output signals, V_{OUT+} and V_{OUT–}. Equation 3 shows the transfer function for V_{DIFF}. By applying the conditions that R_{1} = R_{2} and R_{3} = R_{4}, the transfer function is simplified into Equation 6. Using this configuration, the maximum input signal is equal to the reference voltage and the maximum output of each amplifier is equal to the V_{REF}. The differential output range is 2×V_{REF}. Furthermore, the common mode voltage will be one half of V_{REF} (see Equation 7).

Equation 3.

Equation 4. V_{OUT+} = V_{IN}

Equation 5. V_{OUT–} = V_{REF} – V_{IN}

Equation 6. V_{DIFF} = 2×V_{IN} – V_{REF}

Equation 7.

Linearity over the input range is key for good dc accuracy. The common mode input range and the output swing limitations determine the linearity. In general, an amplifier with rail-to-rail input and output swing is required. Bandwidth is a key concern for this design. Since the NE5532 has a bandwidth of 10 MHz, this circuit will only be able to process signals with frequencies of less than 10 MHz.

Because the transfer function of V_{OUT–} is heavily reliant on resistors (R_{1}, R_{2}, R_{3}, and R_{4}), use resistors with low tolerances to maximize performance and minimize error. This design used resistors with resistance values of 36 kΩ with tolerances measured to be within 2%. But, if the noise of the system is a key parameter, the user can select smaller resistance values (6 kΩ or lower) to keep the overall system noise low. This ensures that the noise from the resistors is lower than the amplifier noise.